## Computational aspects of algebraic curves: [proceedings] by Tanush Shaska

By Tanush Shaska

The improvement of recent computational strategies and higher computing strength has made it attainable to assault a few classical difficulties of algebraic geometry. the most target of this publication is to focus on such computational recommendations concerning algebraic curves. the realm of study in algebraic curves is receiving extra curiosity not just from the maths group, but additionally from engineers and laptop scientists, as a result value of algebraic curves in functions together with cryptography, coding idea, error-correcting codes, electronic imaging, desktop imaginative and prescient, and plenty of extra. This ebook covers a large choice of themes within the sector, together with elliptic curve cryptography, hyper elliptic curves, representations on a few Riemann-Roch areas of modular curves, computation of Hurwitz spectra, producing structures of finite teams, and Galois teams of polynomials, between different issues.

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Elliptic curves with complex multiplication are prominent in primality testing and cryptography [2] and other aspects of algorithmic number theory [6]. Motivated by this, one might seek an algorithm for determining whether a given elliptic curve E over a number field K has complex multiplication. In [5], the author describes two methods. The first is a probabilistic algorithm which runs in polynomial time in the inputs; the second runs in deterministic polynomial time, but the constants appearing in the analysis of the running time are ineffective.

Since X and Y both have good reduction outside S, Gal(K / K) acts on T(X x T(Y via some quotient Gal(E/K) with E unramified outside S. Let R be the subring of End(T^X) x End(TeY) generated over Z € by {p{(r) : o G Gal(E/K)}. We will show that R is in fact generated, again over Z^, by the actions of Frq for primes q of E lying over p € T. By Nakayama's Lemma, it suffices to prove that these Frobenius elements, acting on (TeX/£) x (TeY/£) = X[i](K) x Y[£}(K), generate (R/£)x. Mt{X[£){K)) x Aut(Y[£](K))\ = vg(£)2.