## Exercises in Set Theory by L.E. Sigler

By L.E. Sigler

Ebook via Sigler, L.E.

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Be a proof in 'lOt in which B appears. We shall show, step by step, that the relations A ~ Bk are theorems in 'lO. 8uppose that this has been established for the relations which precede B j , and let us ~how that A ~ B j is a theorem in 'lO. If Bj is an axiom of 'lOt, then B j is either an axiom of'lO or is A. In both cases, A ~ B j is a theorem in 'l9 by applying C9 or C8. If B, is preceded by relations BJ and BJ ~ B j , we know that A ~ Bj and A ~ (BJ ~ B j ) are theorems in 'lO. Hence (Bj~ Bj ) ~ (A ~ B j ) is a theorem in 'l9 by C13.

Adjoin the hypotheses (ylx)R and (zlx)R. y = T and z = T are true, hence y = z is true. ~ Let R be a relation in 'CO. The relation Then "(3x)R and there exists at most one x such that R" is denoted by "there exists exactly one x such that R". If this relation is a theorem in 'CO, R is said to be afunctional relation in x in the theory to. Let R be a relation in fO, and let x be a letter which is not a constant oj fO. g R is junctional in x in to, then R ~ (x = 'tJe(R» is a theorem in fO. Conversely, if for some term T in to which does not contain x, C46.

By aS2 and aS5 (§l, no. 2), (Vly)A is identical with (T' = U') and the proof is complete. ==> «T'lx')R' . . (U'lx')R') The verification that S7 is a scheme is similar. Intuitively, the scheme S6 means that if two objects are equal, they have the same properties. Scheme 87 is more remote from everyday intuition; it means that if two properties R and S of an object x are equivalent, then the distinguished objects 'tx(R) and 'tx(S) (chosen respectively from the objects which satisfy R, and those which satisfy S, if such objects exist) are equal.