Thinking in Java (3rd Edition) (One-Off) by Bruce Eckel
By Bruce Eckel
I do not like computing device books that deal with you love a child: you must battle through chapters and chapters sooner than the writer starts off hard you. now not this one. TIJ reads like a talk, strikes quick and is usually superb you with attention-grabbing programming snippets. Its truly loads of enjoyable to learn and hard to place down!
Undoubtedly the most effective books i have learn in programming.
Read it if you would like a non-dumbed down method of Java.
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Extra info for Thinking in Java (3rd Edition) (One-Off)
ShiftRows( ) transformation rotates AES state rows to the left by a particular number of bytes depending on the row number. 21. As the state elements are represented with bytes, we simulate the shift rows transformation in terms of load and store bytes rather with a logical cyclic shift of 32-bit words. 2. In this process, we multiply each state byte with 0x02 by performing a Galois ﬁeld multiplication in GF(28 ). 4, Complexity of MixColumns( ).
14, we used an analytic method to simulate the E-function. S-Box Mixing In S-Box mixing, we output a 4-bit word from 6-bit input data by using a 2-dimensional S-Box mixing look-up table. 5, we obtain a total of eight 4-bit words (32 bits) from eight 6-bit words (48 bits), by using eight S-Box mixing look-up tables. 12: Simulation code for initial permutation of DES function. 13: Simulation code for ﬁnal permutation of DES function. perform S-Box mixing by combining eight look-up tables into a single big look-up table sb[ ] and accessing the corresponding 4-bit words with appropriate offsets.
The AES state is updated in multiple iterations using the previous transformations. The key expansion (KE) module expands the given key for supplying the keys to all iterations of the AES cipher engine. The number of times the state is iterated in a loop of the AES algorithm depends on what key length (Nk ) we have chosen. , Nk = 4 32-bit words), then we iterate the data (Nr − 1) times, where Nr = Nb + Nk + 2 and Nb = 4. In the AES algorithm, the parameter Nb (= 4) corresponds to the number of rows of state.